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"We have to try and test to find this optimisation of friction, of back-driveability," says David Kehr, president of humanoid robotics. "It's really a big puzzle."
思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。