I found this article on the subject, and decided to turn that data into a visualization, too.
– facial features and expression
。关于这个话题,谷歌浏览器【最新下载地址】提供了深入分析
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Source: Computational Materials Science, Volume 266
思路:先对 nums2 用单调栈求每个元素的下一个更大值,存入 Map 缓存;再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。