«[Президент США Дональд] Трамп втянул американский народ в несправедливую войну с Ираном в результате порывов [премьер-министра Израиля Биньямина] Нетаньяху и его комичных действий. Пусть он сегодня задаст себе вопрос: после того, как за эти несколько дней было убито более 500 американских военнослужащих, актуален ли лозунг "Америка превыше всего" или он превратился в "Израиль превыше всего"?» — говорится в публикации.
When we got bored with going through the trash (cleaner than dumpster diving), we started thinking how to push it. The last two points we went for was the archive and the reception desk. The reception was behind glass, a tall desk, and it seemed inaccessible. Or it would have been, if the door around the corner had been locked. There were locks, but the best lock in the world is worth fuck-all if you don’t use it! We nicked some visitor badges and a few knicknacks, but no money or anything valuable. We are not there to steal, we are there to prove that it could be done. And I believe we did that quite well.
。关于这个话题，WPS下载最新地址提供了深入分析
В России спрогнозировали стабильное изменение цен на топливо14:55
A Riemannian metric on a smooth manifold \(M\) is a family of inner products \[g_p : T_pM \times T_pM \;\longrightarrow\; \mathbb{R}, \qquad p \in M,\] varying smoothly in \(p\), such that each \(g_p\) is symmetric and positive-definite. In local coordinates the metric is completely determined by its values on basis tangent vectors: \[g_{ij}(p) \;:=\; g_p\!\left(\frac{\partial}{\partial x^i}\bigg|_p,\; \frac{\partial}{\partial x^j}\bigg|_p\right), \qquad g_{ij} = g_{ji},\] with the matrix \((g_{ij}(p))\) positive-definite at every point. The length of a tangent vector \(v = \sum_i v^i \frac{\partial}{\partial x^i}\in T_pM\) is then \(\|v\|_g = \sqrt{\sum_{i,j} g_{ij}(p)\, v^i v^j}\).